This is the whole trigger
Begin
If new.pump1 = 'True'
then
Insert into p_id.devices (p_id_id, process_id, fluid_id, status,
process_graphics_id, device_description)
values (new.p_id_id, new.process_id, new.fluid_id, 'Pump #1', '11',
'Pump');
End if;
If new.pump2 = 'True'
then
Insert into p_id.devices (p_id_id, process_id, fluid_id, status,
process_graphics_id, device_description)
values (new.p_id_id, new.process_id, new.fluid_id, 'Pump #2', '11',
'Pump');
End if ;
RETURN NULL;
END;
Bob
----- Original Message -----
From: "Adrian Klaver" <adrian.kla...@gmail.com>
To: "Tom Lane" <t...@sss.pgh.pa.us>
Cc: "Bob Pawley" <rjpaw...@shaw.ca>; "Postgresql"
<pgsql-general@postgresql.org>
Sent: Friday, January 22, 2010 3:01 PM
Subject: Re: [GENERAL] Old/New
On Friday 22 January 2010 2:05:02 pm Tom Lane wrote:
"Bob Pawley" <rjpaw...@shaw.ca> writes:
> Instead I get two identical rows inserted containing the fluid_id =
> '3501' and 'Pump #1'.
Seems like the only way that's possible with the INSERT .. VALUES
formulation is if the trigger function gets executed twice. Maybe you
accidentally created two instances of the trigger? psql's \d on the
table should list the triggers for you.
regards, tom lane
In addition to the above, is there more to the trigger function then what
you
have shown so far?
--
Adrian Klaver
adrian.kla...@gmail.com
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