Glyn Astill <[email protected]> writes:
>> From: Tom Lane <[email protected]>
>> General case: the schema name is used if the type wouldn't be found
>> without it, according to your current search_path.
> However none of that explains why one of the types is returned with the
> schema name and the other is not, both are in the same schema which is in the
> current search_path.
It's difficult to comment on that without a concrete example, but
"visible according to search_path" does not only mean "in a schema
that's in search_path". It also requires "not masked by a similarly
named object appearing earlier in the path".
regards, tom lane
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