On Tue, 2012-09-04 at 21:58 -0400, David Johnston wrote:

> On Sep 4, 2012, at 21:39, Sergio Basurto <sbasu...@soft-gator.com> wrote:
> 
> > I am using regexp_matches in a function like this
> > 
> > create or replace function test (v_string       in text) returns varchar as 
> > $$
> > declare
> > i_strings               text[];
> > i_string                text[];
> >         
> > i_strings := 
> > regexp_matches(v_string,E'[a-zA-Z0-9:\\s\\-\\.#%]*:[A-Za-z0-9\\s\\-\\.#%]+','g');
> 
> You can store a single array value into i_strings.  It does not magically 
> convert a multi-row result into an array.  You can use ARRAY_AGG to do so or 
> execute the query directly as part of the loop while using a "record" 
> variable to store the current row's value(s). 
> 
> >         
> > -- Then I use  the results
> > foreach i_string slice 1 in array i_strings
> > loop
> >         raise notice 'row = %',i_string;
> > end loop;
> >         
> > when I run the function like this:
> > 
> > select test('1:Warehouse1;2:Warehouse2;');
> >         
> > postgresql complains:
> > ERROR:  query "SELECT 
> > regexp_matches(v_string,E'[a-zA-Z0-9:\\s\\-\\.#%]*:[A-Za-z0-9\\s\\-\\.#%]+','g')"
> >  returned more than one row
> > 
> > Why postgres is sending the ERROR?
> >         
> > Off course I am expecting more than one row!, that's why is in a foreach 
> > loop in the first place.
> >         
> > If I run:
> > select 
> > regexp_matches('1:Warehouse1;2:Warehouse2;',E'[a-zA-Z0-9:\\s\\-\\.#%]*:[A-Za-z0-9\\s\\-\\.#%]+','g');
> > regexp_matches 
> > ----------------
> > {1:Warehouse1}
> > {2:Warehouse2}
> > (2 rows)
> > 
> > I am doing something wrong?
> 
> Note that because you do not use grouping in your expression there is only a 
> single array "cell" in each row - but there could be more than one in which 
> case your for-each above would effectively loop through each sub-component of 
> the match.
> 
> > 
> > Regards,
> >        
> 
> David J.
> 

Thanks for your response David, but my doubt arise because if I use this

i_strings text[] := array [[1:Warehouse1],[2:Warehouse2]];

loops without problem. Is not the same thing?

it prints:

NOTICE: row = {1:Warehouse1}
NOTICE: row = {2:Warehouse2}

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