> Deferrability is a property of a constraint, not an index Yes, but creating a unique constraint implicitly creates an index, and creating a unique index implicitly creates a constraint. So I'm wondering whether I can create a pair where the index is partial and the constraint is deferrable. It sounds like the answer is no? Is there a workaround where I first create one and then alter the other one?
Thanks, Paul -- _________________________________ Pulchritudo splendor veritatis. -- Sent via pgsql-general mailing list (pgsql-general@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-general
