Let's say I have a table :

create table people (
person_id integer not null primary key,
firstnames varchar(50),
lastname varchar(50)
);

and another

create table partners (
first_person integer not null references people(person_id),
second_person integer not null reference people(person_id)
);

Let's do some test data:

select setval('people_seq',0);
insert into people (person_id, firstnames, lastname) values 
(nextval('people_seq'), 'Prince Of', 'Darkness');
insert into people (person_id, firstnames, lastname) values 
(nextval('people_seq'), 'William Henry', 'Gates');
insert into people (person_id, firstnames, lastname) values 
(nextval('people_seq'), 'Steve', 'Case');

insert into partners (first_person, second_person) values (1,2);
insert into partners (first_person, second_person) values (1,3);

Now is it possible for me to do a select statement without any 
subqueries to get the firstnames and lastname of each member of a 
partnership. e.g.

first_firstnames | first_lastname | second_firstnames | second_lastname
-----------------+----------------+-------------------+----------------
Prince Of        | Darkness       | William Henry     | Gates
Prince Of        | Darkness       | Steve             | Case

Thanks for any help anybody can give...

-jag

-- 
--------------------------------------------------------
Joshua Ginsberg                 [EMAIL PROTECTED]
Director of Technology          [EMAIL PROTECTED]
Student Association             AIM: L0stInTheDesert
Rice University, Houston, TX    Cellphone: 713.478.1769
========================================================
"Programming today is a race between software engineers
striving to build bigger and better idiot-proof programs
and the Universe trying to produce bigger and better
idiots. So far, the Universe is winning." -Rich Cook
--------------------------------------------------------


---------------------------(end of broadcast)---------------------------
TIP 5: Have you checked our extensive FAQ?

http://www.postgresql.org/users-lounge/docs/faq.html

Reply via email to