On Thu, 20 Nov 2003 16:52:37 +0900, Alex <[EMAIL PROTECTED]> wrote:
>>>>Is there an easy way to write a select statement that returns me the
>>>>frist free number or any within the range of 200?
>>>>For example if 1-30, and 32-50 are occupied then i would like to fill in
>>>>the new entry with id 31.
Fortunately this is not the performance mailing list :-)
First free number:
SELECT max(t1.id) + 1
FROM t AS t1 INNER JOIN t AS t2
ON (t1.id < 200 AND t1.id < t2.id AND t2.id <= 200)
GROUP BY t2.id
HAVING max(t1.id) + 1 < t2.id
ORDER BY t2.id
LIMIT 1;
Make sure that there is always a row with id=0 and a row with id=200.
Any free number:
SELECT id - 1
FROM t
WHERE 1 < id AND id <= 200
AND NOT EXISTS (SELECT * FROM t AS t2 WHERE t2.id = t.id - 1)
LIMIT 1;
Always having a row with id=200 helps avoid unwanted corner cases.
One more:
SELECT coalesce(max(id), 0) + 1
FROM t
WHERE id <= 200
AND id = (SELECT count(*) FROM t AS t2 WHERE t2.id <= t.id);
This should work without any dummy rows. And it will not work, if id
is not unique or there is any row with id < 1.
Servus
Manfred
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