Assuming identification_number is a unique (primary) key...
select * from my_table where date_of_birth in (select date_of_birth from my_table group by date_of_birth having count(*) > 1)
Or - it may be quicker to do...
select * from my_table a where exists (select 'x' from my_table b where a.date_of_birth = b.date_of_birth group by b.date_of_birth having count(*) > 1)
Kall, Bruce A. wrote:
I've look for a solution to this, but have only been able to find solutions to delete duplicate entries in a table by deleting entries not returned by SELECT DISTINCT.
What sql should I use to SELECT entries in a table that have two particular column values that match?
For example, my_table has
name, phone number, identification_number, zip code, date of birth, and city
I want to SELECT rows from this table that have the same values in identification and date of birth (duplicates) so I can have the user look at them in order to figure out which one to delete.
I tried something like:
$db_sql = "SELECT * FROM my_table GROUP BY identification_number HAVING count(date_of_birth) > 1 ORDER BY name"
but that doesn't seem to work.
Thanks, Bruce
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