my function is very long but i found an example with the same comportment : CREATE OR REPLACE FUNCTION adoc.totoTest() RETURNS int4 AS $BODY$ my $var = '->>>'; &concat($var);
sub concat { $var .= 'tagada'; } elog NOTICE, $var; return 4;
$BODY$
LANGUAGE 'plperl' VOLATILE;
first execution : ->>>tagada
second execution : ->>>
In the example above $var in sub concat is NOT an argument provided to the function. What you've done there is create a named closure (if I'm getting my terms right) in which the inner $var is allocated on first call but not afterwards. The second time you run totoTest() the outer $var (my $var) is a new variable, whereas the inner one still refers to the original.
If you actually want to return a concatenated string you'd want something like:
sub concat {
my $var = shift;
return $var . 'tagada';
}If you want to affect an outer variable you'll want something like
sub concat {
my $var_ref = shift;
$$var_ref .= 'tagada';
}Does that help? -- Richard Huxton Archonet Ltd
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