Nope... It returns 0 rows when there are no rows in log_stop with stoptype =
1...
BTJ
Scott Marlowe wrote:
> On Mon, 2005-04-18 at 11:24, BjÃrn T Johansen wrote:
>
>>I need a select like this..:
>>
>>select ordre.id, ordre.desc, log_stop.stoptype from ordre left outer join
>>log_stop on
>>ordre.id = log_stop.ordreid where ordre.id = 22
>>
>>The problem is that I need to include "where log_stop.stoptype = 1". So if
>>log_stop
>>includes 3 rows with stoptype = 1 and ordreid = 22, my select should return 3
>>rows.
>>Also, if log_stop includes 3 rows with stoptype = 1 and 2 rows with stoptype
>>= 2, my
>>select should still return 3 rows. And if there are 0 rows with stoptype = 1,
>>my
>>select should return 1 row.
>
>
> Would this work?
>
> select ordre.id, ordre.desc, log_stop.stoptype from ordre left outer join
> log_stop on
> ordre.id = log_stop.ordreid where ordre.id = 22 AND
> COALESCE(log_stop.stoptype,1)=1
>
>
---------------------------(end of broadcast)---------------------------
TIP 2: you can get off all lists at once with the unregister command
(send "unregister YourEmailAddressHere" to [EMAIL PROTECTED])