On Thu, Feb 09, 2006 at 09:51:13PM -0500, Stephen Frost wrote:
> * David Rio Deiros ([EMAIL PROTECTED]) wrote:
> > Now I have to redefine my query because I want to get the second 
> > output but keeping the group_id. Ideas and suggestions are welcome.
> 
> You might want to look at 'distinct on'.

I am reading about it right now. It sounds that it will make it.

Thanks guys for your help,

David


---------------------------(end of broadcast)---------------------------
TIP 4: Have you searched our list archives?

               http://archives.postgresql.org

Reply via email to