On Mon, 2006-03-20 at 21:10, Wei Wei wrote:
> In a query, there is something like
>
> order by count(id)/age
>
> where both id and age are the integer data type.
>
> >From a query result, I believe the operation count(id)/age yields a integer.
> >I need it in real data type. After searching the online document, I haven't
> >found any related information. Can someone help me out on this problem,
> >please.
>
> Thanks,
>
> w
Try:
order by count(id)/age::float
regards,
Sig.Gunn
---------------------------(end of broadcast)---------------------------
TIP 9: In versions below 8.0, the planner will ignore your desire to
choose an index scan if your joining column's datatypes do not
match
