On Thu, Mar 10, 2011 at 05:51:31PM -0500, Tom Lane wrote: > No, that's not what I'm on about. Consider > > (((A COLLATE X) || B) || (C COLLATE Y)) < (D COLLATE Z) > > (I've spelled out the parenthesization in full for clarity, but most > of these parens could be omitted.) Is this expression legal, or > should the "<" operator be throwing an error for conflicting > explicitly-derived collations? Our code as it stands will take it, > because no individual operator sees more than one COLLATE among its > arguments. But I'm not sure this is right. The only text I can find > in SQL2008 that seems to bear on the point is in 4.2.2:
The rules are essentially as described here: http://msdn.microsoft.com/en-us/library/ms179886.aspx So: (A COLLATE X) => collation X ((A COLLATE X) || B) => collation X (((A COLLATE X) || B) || (C COLLATE Y)) => error If we aren't erroring on this then we're doing it wrong. The whole point of going through the parse tree and assigning a collation to each node is to catch these things. > As I read this, the collation attached to any Var clause is implicit > (because it came from the Var's data type), and the collation attached > to a CollateClause is presumably explicit, but where does it say what > happens at higher levels in the expression tree? It's at least arguable > that the result collation of an expression is explicit if its input > collation was explicit. The fact that the default in case of doubt > apparently is supposed to be "explicit" doesn't give any aid or comfort > to your position either. If explicitness comes only from the immediate > use of COLLATE, why don't they say that? This is worded to make one > think that most cases will have explicit derivation, not only COLLATE. See 9.3 "Data types of results of aggregations" clause (ii). It contains essentially the rules outlined by the Transact-SQL page above. The collation derivation and declared type collation of the result are determined as follows. Case: 1) If some data type in DTS has an explicit collation derivation and declared type collation EC1, then every data type in DTS that has an explicit collation derivation shall have a declared type collation that is EC1. The collation derivation is explicit and the collation is EC1. 2) If every data type in DTS has an implicit collation derivation, then Case: A) If every data type in DTS has the same declared type collation IC1, then the collation derivation is implicit and the declared type collation is IC1. B) Otherwise, the collation derivation is none. 3) Otherwise, the collation derivation is none. In my implementation I needed to expand this to the general set of operators postgresql supported and relaxed this to only consider arguments to the function/operator that had the same type as the resulting type of the function/operator, since that's the only thing that makes sense. A concatination then requires its arguments to be compatible. A substr has the collation of its sole string argument. I hope this helps, Have a nice day, -- Martijn van Oosterhout <klep...@svana.org> http://svana.org/kleptog/ > Patriotism is when love of your own people comes first; nationalism, > when hate for people other than your own comes first. > - Charles de Gaulle
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