Andrew Dunstan <[EMAIL PROTECTED]> writes:gcc version 3.2.2 20030222 (Red Hat Linux 3.2.2-5)
Tom Lane wrote:
I've been able to reproduce this on one of my machines, and it's nasty.
In that case I'm confused about why this code compiles on my machine:
What compiler are you using? I'm using gcc 2.95.3 (on the machine that shows the failure), and I think Bruce is also using something less than the latest. It's possible that more recent gcc's are able to figure out that the reference to free_func should be interpreted as a parameter name and not a typedef.
In fact, trying your test program fails here:
$ gcc -Wall zzz.c
zzz.c:8: parse error before `free_func'
zzz.c:8: parse error before `)'
$
so "compiler difference" definitely seems to be the answer.
cheers
andrew
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