Have we made any progress on this? ---------------------------------------------------------------------------
Tom Lane wrote: > Michael Glaesemann <[EMAIL PROTECTED]> writes: > > ... I think this just confirms that there is some kind of rounding (or > > lack of) in interval_div. Kind of frustrating that it's not visible > > in the result. > > I think the fundamental problem is that the float8 results of division > are inaccurate, and yet we're assuming that we can (for instance) coerce > them to integer and get exactly the right answer. For instance, in the > '41 months'/10 example, I get month_remainder_days being computed as > > (gdb) p month_remainder > $19 = 0.099999999999999645 > (gdb) s > 2575 result->day += (int32) month_remainder_days; > (gdb) p month_remainder_days > $20 = 2.9999999999999893 > > The only way we can really fix this is to be willing to round off > the numbers, and I think the only principled way to do that is to > settle on a specific target accuracy, probably 1 microsecond. > Then the thing to do would be to scale up all the intermediate > float results to microseconds and apply rint(). Something like > (untested) > > month_remainder = rint(span->month * USECS_PER_MONTH / factor); > day_remainder = rint(span->day * USECS_PER_DAY / factor); > result->month = (int32) (month_remainder / USECS_PER_MONTH); > result->day = (int32) (day_remainder / USECS_PER_DAY); > month_remainder -= result->month * USECS_PER_MONTH; > day_remainder -= result->day * USECS_PER_DAY; > > /* > * Handle any fractional parts the same way as in interval_mul. > */ > > /* fractional months full days into days */ > month_remainder_days = month_remainder * DAYS_PER_MONTH; > extra_days = (int32) (month_remainder_days / USECS_PER_DAY); > result->day += extra_days; > /* fractional months partial days into time */ > day_remainder += month_remainder_days - extra_days * USECS_PER_DAY; > > #ifdef HAVE_INT64_TIMESTAMP > result->time = rint(span->time / factor + day_remainder); > #else > result->time = rint(span->time * 1.0e6 / factor + day_remainder) / > 1.0e6; > #endif > > This might need a few more rint() calls --- I'm assuming that float ops > with exact integral inputs will be OK, which is an assumption used > pretty widely in the datetime code, but ... > > Per the comment, if we do this here we probably want to make > interval_mul work similarly. > > regards, tom lane -- Bruce Momjian [EMAIL PROTECTED] EnterpriseDB http://www.enterprisedb.com + If your life is a hard drive, Christ can be your backup. + ---------------------------(end of broadcast)--------------------------- TIP 2: Don't 'kill -9' the postmaster
