Neil Conway <[EMAIL PROTECTED]> writes:
> This code is inefficient, however: length() requires iterating through
> the entire list, so this code scans both lists twice. The attached patch
> improves this by implementing equal() with a single scan of both lists.
You have effectively reverted the code to its previous slow state.
The problem with what you've done is that it recursively applies equal()
to the list contents, which may take a very large number of cycles, only
to eventually fail because one list is a prefix of the other. The point
of the current coding is to detect that condition before we recurse.
regards, tom lane
---------------------------(end of broadcast)---------------------------
TIP 7: don't forget to increase your free space map settings
