Greg Stark <[EMAIL PROTECTED]> writes:
> slo=> explain analyze select * from region, (select 1 union all select 2) as x;
> QUERY PLAN
>
> ------------------------------------------------------------------------------------------------------------------------
> Nested Loop (cost=0.00..11162.00 rows=5534 width=108) (actual time=0.13..541.19
> rows=5534 loops=1)
> -> Subquery Scan x (cost=0.00..2.00 rows=2 width=0) (actual time=0.03..0.08
> rows=2 loops=1)
> -> Append (cost=0.00..2.00 rows=2 width=0) (actual time=0.02..0.05 rows=2
> loops=1)
> -> Subquery Scan "*SELECT* 1" (cost=0.00..1.00 rows=1 width=0)
> (actual time=0.01..0.02 rows=1 loops=1)
> -> Result (cost=0.00..1.00 rows=1 width=0) (actual
> time=0.01..0.01 rows=1 loops=1)
> -> Subquery Scan "*SELECT* 2" (cost=0.00..1.00 rows=1 width=0)
> (actual time=0.01..0.02 rows=1 loops=1)
> -> Result (cost=0.00..1.00 rows=1 width=0) (actual
> time=0.01..0.01 rows=1 loops=1)
> -> Seq Scan on region (cost=0.00..2813.00 rows=2767 width=104) (actual
> time=0.03..123.44 rows=2767 loops=2)
> Total runtime: 566.24 msec
> (9 rows)
> Wouldn't it be faster to drive the nested loop the other way around?
You seem to be using a rather wacko value of cpu_tuple_cost; those
Result nodes ought to be costed at 0.01 not 1.00. With the default
cost settings I get an other-way-around plan for a similar test.
(I used tenk1 from the regression database as the outer table.)
However, it looks to me like the subquery-scan-outside plan probably
is the faster one, on both my machine and yours. I get
regression=# explain analyze select * from tenk1, (select 1 union all select 2) as x;
QUERY PLAN
----------------------------------------------------------------------------------------------------------------------------
Nested Loop (cost=0.00..858.00 rows=20000 width=248) (actual time=0.42..3648.61
rows=20000 loops=1)
-> Seq Scan on tenk1 (cost=0.00..458.00 rows=10000 width=244) (actual
time=0.23..199.97 rows=10000 loops=1)
-> Subquery Scan x (cost=0.00..0.02 rows=2 width=0) (actual time=0.07..0.24
rows=2 loops=10000)
-> Append (cost=0.00..0.02 rows=2 width=0) (actual time=0.05..0.17 rows=2
loops=10000)
-> Subquery Scan "*SELECT* 1" (cost=0.00..0.01 rows=1 width=0)
(actual time=0.03..0.06 rows=1 loops=10000)
-> Result (cost=0.00..0.01 rows=1 width=0) (actual
time=0.01..0.02 rows=1 loops=10000)
-> Subquery Scan "*SELECT* 2" (cost=0.00..0.01 rows=1 width=0)
(actual time=0.03..0.06 rows=1 loops=10000)
-> Result (cost=0.00..0.01 rows=1 width=0) (actual
time=0.01..0.02 rows=1 loops=10000)
Total runtime: 3807.39 msec
(9 rows)
regression=# set cpu_tuple_cost = 1;
SET
regression=# explain analyze select * from tenk1, (select 1 union all select 2) as x;
QUERY PLAN
------------------------------------------------------------------------------------------------------------------------
Nested Loop (cost=0.00..40718.00 rows=20000 width=248) (actual time=0.39..1214.42
rows=20000 loops=1)
-> Subquery Scan x (cost=0.00..2.00 rows=2 width=0) (actual time=0.10..0.31
rows=2 loops=1)
-> Append (cost=0.00..2.00 rows=2 width=0) (actual time=0.06..0.22 rows=2
loops=1)
-> Subquery Scan "*SELECT* 1" (cost=0.00..1.00 rows=1 width=0)
(actual time=0.05..0.08 rows=1 loops=1)
-> Result (cost=0.00..1.00 rows=1 width=0) (actual
time=0.03..0.04 rows=1 loops=1)
-> Subquery Scan "*SELECT* 2" (cost=0.00..1.00 rows=1 width=0)
(actual time=0.05..0.08 rows=1 loops=1)
-> Result (cost=0.00..1.00 rows=1 width=0) (actual
time=0.02..0.03 rows=1 loops=1)
-> Seq Scan on tenk1 (cost=0.00..10358.00 rows=10000 width=244) (actual
time=0.17..188.37 rows=10000 loops=2)
Total runtime: 1371.17 msec
(9 rows)
The flipover point between the two plans is cpu_tuple_cost = 0.04 in
my tests.
It looks to me like we've neglected to charge any cost associated with
Subquery Scan or Append nodes. Certainly Subquery Scan ought to charge
at least a cpu_tuple_cost per row. Perhaps Append ought to as well ---
although since it doesn't do selection or projection, I'm not quite sure
where the time is going in that case. (Hmmm... time to get out the
profiler...)
regards, tom lane
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