Simon, > Could it be that we have overlooked this simple explanation and that the > Haas and Stokes equation is actually quite good, but just not being > applied?
That's probably part of it, but I've tried Haas and Stokes on a pure random sample and it's still bad, or more specifically overly conservative. -- --Josh Josh Berkus Aglio Database Solutions San Francisco ---------------------------(end of broadcast)--------------------------- TIP 1: subscribe and unsubscribe commands go to [EMAIL PROTECTED]
