Eric try:
select num, p1,p2 ... from contacts inner join groups using (contacts.num=groups.contactNum) where groups.groupNum=a and contact.p3=b and not exists ( select 1 from groups g2 where g2.contactNum = groups.contactNum and g2.groupNum != a); or select num, p1,p2 ... from contacts inner join groups using (contacts.num=groups.contactNum) where groups.groupNum=a and contact.p3=b and groups.groupNum in ( select contactNum from groups group by contactNum having count(*) = 1); The IN version may still be faster as the sub-select should be evaluated only once; JLL eric soroos wrote: > > I'm having trouble subtracting groups from other groups. > > I've got a data model that has the following essential features: > > create table contacts (num int, properties....); > create table groups (groupNum int, contactNum int); > > Where not all contacts will be in a group, some groups will contain most contacts, >and there will be something like hundreds of groups and tens of thousands of >contacts. I allow people to build groups using criteria, which I need to >programatically translate to sql. > > One somewhat common pattern is: > > Select all contacts in group a, who have property b, and who aren't in groups >c,d,e,f... > > My first shot was subqueries: > > select num, p1,p2 ... from contacts > inner join groups using (contacts.num=groups.contactNum) > where groups.groupNum=a > and contact.p3=b > and not num in (select contactNum from groups where groupNum=c) > and not num in (select contactNum from groups where groupNum=d) > and not num in (select contactNum from groups where groupNum=e) > and not num in (select contactNum from groups where groupNum=f) > > This is .... slow. agonizingly so. > > With an inner join, I'm not convinced that the subtraction is actually correct., but >it is much faster. Unfortunatley, faster incorrect answers are rarely helpful. > > Outer joins seem even worse than subselects for speed, but it does appear to give >the correct answer. (example with a single join.) > > select num from contacts > left outer join groups > on (contacts.num=groups.contactNum > and groups.groupNum=b) > where > dl_groupDonor._groupNum is null > and p3=c > > I've got to be missing something here, because this is much slower from the (slow) >procedural system that I'm porting from. > > I've been avoiding using union / intersect since I don't really ever know what >columns are going to be in the query. perhaps I should revisit that decision and try >to work around it. > > eric > > ---------------------------(end of broadcast)--------------------------- > TIP 2: you can get off all lists at once with the unregister command > (send "unregister YourEmailAddressHere" to [EMAIL PROTECTED]) ---------------------------(end of broadcast)--------------------------- TIP 1: subscribe and unsubscribe commands go to [EMAIL PROTECTED]