Gary Stainburn wrote:
On Friday 07 Feb 2003 10:48 am, Tomasz Myrta wrote:
<cut>
Hi Tomasz,
I don't think you understand what I mean.
The history table could be thought of as the following SQL statement if the
data had actually existed. This table actually represents a manually input
summary of the pre-computerised data.
insert into history
select rosid, rojid, count(*) from roster_staff group by rssid, rsgsid;
If I have a history of
hsid | hjid | hcount
------+------+--------
1 | 2 | 3
1 | 3 | 1
5 | 5 | 4
6 | 5 | 3
9 | 4 | 4
14 | 5 | 4
and I have a roster of
rodate | rogid | rojid | rosid
-----------+-------+-------+-------
2003-02-15 | 1 | 2 | 1
2003-02-15 | 1 | 5 | 5
2003-02-16 | 1 | 5 | 1
I want my view to show
hsid | hjid | hcount
------+------+--------
1 | 2 | 4
1 | 3 | 1
1 | 5 | 1
5 | 5 | 5
6 | 5 | 3
9 | 4 | 4
14 | 5 | 4
I understood your problem well and I just thought some idea will be enough to continue work.
Here is detailed query for your problem:
create view some_view as
select
coalesce(hjid,rjid) as jid,
coalesce(hsid,rsid) as sid,
coalesce(hcount,1)+count(*)-1 as hcount
from
history
full outer join roster on (hjid=rjid and hsid=rosid)
group by hjid,rjid,hsid,rosid;
Regards,
Tomasz Myrta
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