On Fri, 1 Aug 2003, Josh Berkus wrote:
> Thomas,
>
> > than now()? I'm looking for something along the lines of:
> > SELECT to_char('2003-08-04', 'Day') without much success.
> >
>
> Well, you could try the online docs under "Functions and operators" <grin>.
Hey Josh, how goes...yeah I bumbled around date/time functions for awhile but
couldn't find the right syntax...maybe I need new glasses? ;-)
> Alternately, SELECT EXTRACT(dow FROM '2003-08-04') will give you a numerical
> (0-6) day of the week.
I tried this but I don't need an integer returned so I went with the
to_char() approach. Thanks for tip - and thanks to Rod as well.
On 1 Aug 2003, Rod Taylor wrote:
>
> SELECT to_char('2003-08-04'::date, 'Day');
>
This is what I went for as it is the closest to the MySQL/Oracle syntax
I use for the same purpose, particularly Oracle:
$query = qq |SELECT DATE_FORMAT('$start_date', '%W')| if ($dbtype eq 'mysql');
$query = qq |SELECT TO_CHAR('start_date'::date, 'Day') if ($dbtype eq 'postgres');
$query = qq |SELECT TO_CHAR(TO_DATE('$start_date'), 'Day') FROM DUAL| if ($dbtype eq
'oracle');
Thanks again fellas - have a nice weekend!
Cheers
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