Re: [SQL] how to get decimal to date form

[Tomasz Myrta]

In our postgre database is a decimal field with format YYMMDDhhmmss.9999999999
where the 9s are random digits.  I'm trying to strip off just the
YYMMDD and put it in date form.
So far I came up with:
SUBSTR(TO_CHAR(rec_num,99999999999),1,6) AS Date which returns YMMDD.
For example where the rec_num is 30608124143.47069519725 the above
functions return 30608.
I tried wrapping another TO_CHAR around it to try to format it to a
date but this seems like it's a bit much for this purpose.
Any suggestions would be appreciated.

-David
1. replace 0 with 9 to get leading zeroes - 030608 instead of 30608

2. to_date('030608','YYMMDD');

Regards,
Tomasz Myrta
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