Re: [SQL] Order by YYYY MM DD in reverse chrono order trouble

[Edmund Bacon]

Is there some reason you can't do this:

SELECT DISTINCT
 date_part('year', uu.add_date),  date_part('month', uu.add_date), 
 date_part('day', uu.add_date)

 FROM uus INNER JOIN ui ON uus.user_id=ui.id INNER JOIN uu ON
 ui.id=uu.user_id
 WHERE uus.x_id=1
 ORDER BY 
	uu.add_date DESC;

This might be faster, as you only have to sort on one field, and I think it should give the desired results

[EMAIL PROTECTED] wrote:

Hello,

I am trying to select distinct dates and order them in the reverse
chronological order.  Although the column type is TIMESTAMP, in this
case I want only YYYY, MM, and DD back.
I am using the following query, but it's not returning dates back in
the reverse chronological order:
SELECT DISTINCT
 date_part('year', uu.add_date),  date_part('month', uu.add_date), 
 date_part('day', uu.add_date)

FROM uus INNER JOIN ui ON uus.user_id=ui.id INNER JOIN uu ON
ui.id=uu.user_id
WHERE uus.x_id=1
ORDER BY
date_part('year', uu.add_date), date_part('month', uu.add_date), 
date_part('day',  uu.add_date) DESC;

This is what the above query returns:

date_part | date_part | date_part
-----------+-----------+-----------
     2004 |         2 |         6
     2004 |         4 |        20
(2 rows)
I am trying to get back something like this:
2004 4 20
2004 4 19
2004 2 6
...
My query is obviously wrong, but I can't see the mistake.  I was
wondering if anyone else can see it.  Just changing DESC to ASC, did
not work.
Thank you!
Otis
---------------------------(end of broadcast)---------------------------
TIP 2: you can get off all lists at once with the unregister command
   (send "unregister YourEmailAddressHere" to [EMAIL PROTECTED])
 

--
Edmund Bacon <[EMAIL PROTECTED]>
---------------------------(end of broadcast)---------------------------
TIP 1: subscribe and unsubscribe commands go to [EMAIL PROTECTED]