On Wednesday 21 April 2004 21:07, Kemin Zhou wrote:Here I have a very simple case
table1 table1_removed
anotherTable
create or replace RULE rec_remove as ON DELETE TO table1 do insert into table1_remove select old.*, a.acc from old g join anotherTable a on g.acc=a.other_acc; === the parser complained ERROR: relation "*OLD*" does not exist So I used select old.*, a.acc from table1 g join anotherTable a on g.acc=a.other_acc;
This worked find.
When I run delete on table1, 213 rows.
tmp table received 213X213 = 45369 rows. each row is duplicated 213 times.
The issue here is that although you can refer to values such as OLD.acc, OLD is not a table but more like single row. So, you probably want
...DO INSERT INSTO table1_remove
SELECT old.*, a.acc FROM anotherTable a WHERE a.other_acc = OLD.acc;
Old is not a single row at all, it is a placeholder for the result set that is deleted in this case. The rule you probably want is:
create rule rec_remove as on delete to table1
do insert into table1_remove select old.*, a.acc
from anotherTable a where old.acc = a.other_acc;This unfortunately does NOT support all the other join types, since the parser does not let you use JOIN before any FROM and you have old already in your rangetable, even if you don't see it.
Jan
Your second example just ignored the OLD.acc altogether in the join, so of course you got an unconstraind join of 213 x 213.
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---------------------------(end of broadcast)--------------------------- TIP 9: the planner will ignore your desire to choose an index scan if your joining column's datatypes do not match
