Indeed, it seems that I get the same result for a similar query. I'm running version 7.3.4 on a rh 9 server.
Also: is the function date_part a function you wrote yourself? I get an error stating that the function date_part("Unknown",date) is not recognized. It maybe not a solution to the actual problem but you could try this: save the date and the time in two seperate fields. I use a similar construction for convenience. Regards, Stijn. > Hello, > > Hm, doesn't work for me: > > [EMAIL PROTECTED] mydb=> select distinct date_part('year', uu.add_date), > date_part('month', uu.add_date), date_part('day', > uu.add_date) from uus inner join ui on uus.user_id=ui.id > inner join > uu on ui.id=uu.user_id where uus.subscriber_user_id=1 order by > uu.add_date desc; > > ERROR: For SELECT DISTINCT, ORDER BY expressions must appear > in target > list > > I have this version of PostgreSQL installed: postgresql-7.3.4-3.rhl9 > > Thanks, > Otis > > > --- Tom Lane <[EMAIL PROTECTED]> wrote: > > <[EMAIL PROTECTED]> writes: > > > I'd love to be able to do that, but I cannot just ORDER BY > > uu.add_date, > > > because I do not have uu.add_date in the SELECT part of the > > statement. > > > > Sure you can. Back around SQL89 there was a restriction that ORDER > > BY > > values had to appear in the SELECT list as well, but no modern > > database > > has such a restriction anymore ... > > > > regards, tom lane > > > ---------------------------(end of > broadcast)--------------------------- > TIP 5: Have you checked our extensive FAQ? > > http://www.postgresql.org/docs/faqs/FAQ.html > ---------------------------(end of broadcast)--------------------------- TIP 8: explain analyze is your friend