Mark Dilger wrote:
[EMAIL PROTECTED] wrote:
Hi.
How can I sum a row and show the sum for each row???
For example, in a finances table that have the total
movimentation(debit/credit)
in the bank.
i.e:
CREATE TABLE TB1 (id integer primary key, value numeric);
insert into tb1 values (1,20);
insert into tb1 values (2,2);
insert into tb1 values (3,3);
insert into tb1 values (4,17);
insert into tb1 values (5,-0.5);
insert into tb1 values (6,3);
I want a query that returns:
-id- | --- value --- | --- subtot ---
1 | 20.00 | 20.00
2 | 2.00 | 22.00
3 | 3.00 | 25.00
4 | 17.00 | 42.00
5 | -0.50 | 41.50
6 | 3.00 | 44.50
The subtot colum will be the "prev. subtot colum"+"value colum". :-/
I dont know how to make the "subtot" colum, I tried to use the sum()
function
but it not works correctly.
Any idea???
Thanks.
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CREATE TABLE tb1 (id integer primary key, value numeric);
CREATE TYPE subtotal_type AS (id integer, value numeric, subtotal numeric);
CREATE OR REPLACE FUNCTION subtotal () RETURNS SETOF subtotal_type AS $$
DECLARE
tbrow RECORD;
sbrow subtotal_type;
BEGIN
sbrow.subtotal := 0;
FOR tbrow IN
SELECT id, value FROM tb1 ORDER BY id
LOOP
sbrow.id := tbrow.id;
sbrow.value := tbrow.value;
sbrow.subtotal := sbrow.subtotal + tbrow.value;
RETURN NEXT sbrow;
END LOOP;
RETURN;
END;
$$ LANGUAGE plpgsql;
insert into tb1 (id, value) values (1, 20.0);
insert into tb1 (id, value) values (2, 2.0);
insert into tb1 (id, value) values (3, 3.0);
select * from subtotal();
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I forgot to mention that you must run 'createlang plpgsql' on the
database for this to work, if the language named plpgsql has not already
been created. (This command would typically be run from a shell, such
as sh, bash, etc., and not from within psql.)
Please review
http://www.postgresql.org/docs/8.0/interactive/app-createlang.html for
more information about this command.
Cheers!
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