Michael Fuhr <[EMAIL PROTECTED]> writes:
> I don't know if there's an easier way to check if an int2 is a
> member of an int2vector, but you could write a function to convert
> an int2vector to an int2 array and then use an "= ANY" expression.
FWIW, as of 8.1 an int2vector *is* an int2 array, so = ANY just works.
regards, tom lane
---------------------------(end of broadcast)---------------------------
TIP 9: In versions below 8.0, the planner will ignore your desire to
choose an index scan if your joining column's datatypes do not
match
