Nevermind, I figured out that I just needed to do it like this:
SELECT to_char( logtime, 'Dy'),count(*),to_char( logtime, 'D') FROM
sclog WHERE date_trunc('day', logtime) > current_date + '7 day
ago'::interval group by to_char( logtime, 'Dy'),to_char( logtime, 'D')
ORDER BY to_char( logtime, 'D') DESC;
It is interesting that I can't put to_char( logtime, 'D') in the the
group by without putting it in the select.
Joseph Shraibman wrote:
p8:owl=>SELECT to_char( logtime, 'Dy'),count(*) FROM logtab WHERE
date_trunc('day', logtime) > current_date + '7 day ago'::interval group
by to_char( logtime, 'Dy') ORDER BY to_char( logtime, 'Dy') DESC;
to_char | count
---------+-------
Wed | 1447
Tue | 618
Thu | 1161
Sun | 230
Sat | 362
Mon | 760
Fri | 1281
(7 rows)
The problem is that I want those results sorted in day of week order,
not text order of the day name, so I tried this:
p8:owl=>SELECT to_char( logtime, 'Dy'),count(*) FROM sclog WHERE
date_trunc('day', logtime) > current_date + '7 day ago'::interval group
by to_char( logtime, 'Dy') ORDER BY to_char( logtime, 'D') DESC;
ERROR: column "sclog.logtime" must appear in the GROUP BY clause or be
used in an aggregate function
Now obviously I don't want to group by logtime (a timestamp) so how do I
work around this? What I really need is a function that converts from
the char representation to a day of week number or vice versa. I also
have the same problem with month names.
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