The pgsql function is compiled and wouldn't know how to handle a table
name as a variable.
If you rewrite the SQL to use the 'EXECUTE' statement I think you could
do this, something along the lines of (untested):
EXECUTE ''INSERT INTO '' || quote_ident(tmplist) || '' (SELECT * FROM
links WHERE p=x)'';
Thanks. Yet, if I give the table name as the argument, I get the same
error.
drop function traverse(integer, text);
create or replace function traverse (integer, text)
returns integer as
$$
declare
x int;
tname alias for $2;
begin
x := $1;
while x is not null loop
select n into x from links where p = x;
insert into tmplink (select * from links where p=x);
EXECUTE ''INSERT INTO '' || quote_ident(tname) || '' (SELECT * FROM
links WHERE p=x)'';
end loop;
return 1 ;
end;
$$
language plpgsql;
The above gives the following error. Please note that the first and
second args are mixed up now. I tested it only on 8.0 (FC 4) and didn't on
8.1 and wonder whether it's a bug or I may be doing something wrong.
Using tname or $2 doesn't change the result.
========================================================================
# select traverse(0, 'links2');
ERROR: syntax error at or near "INSERT" at character 11
QUERY: SELECT ''INSERT INTO '' || quote_ident( $1 ) || '' (SELECT * FROM
links WHERE p= $2 )''
CONTEXT: PL/pgSQL function "traverse" line 10 at execute statement
LINE 1: SELECT ''INSERT INTO '' || quote_ident( $1 ) || '' (SELECT ...
========================================================================
Regards,
Ben K.
Developer
http://benix.tamu.edu
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