> > an inspection node (each row in t_inspect is an
> > inspection node) that has passed can't have a new
> > defect added - since it has already passed.  
> > 
> > therefore, in the defect entry form, i only want
> to
> > display those inspection nodes that don't have a
> true
> > value.  by definition, a true value will always be
> the
> > last (by time) inspect_result.
> > 
> > therefore, i need all the inspect nodes that don't
> yet
> > have a true value (iow, a true value in the last
> (by
> > time) inspect_result_pass row).
> > 
> > an inspection node can have multiple inspection
> > results, hence, the t_inspection_results table.
> > 
> > this might seem counter-intuitive at first, but it
> > makes sense since it may take 5 tries to
> eventually
> > pass a particular inspection node (f, f, f, f, t)
> for
> > fucntional test, for example.  one node, five
> tests to
> > pass it.
> 
> here is a test I did. bye the way, I did this is
> access as it is the only source available to me
> at the moment.
> 
> table = test
> id_i  ir_id   test    stamp
> 1     1       No      6/5/2006 1:00:00 AM
> 1     2       No      6/5/2006 2:00:00 AM
> 1     3       Yes     6/5/2006 4:00:00 AM
> 2     4       Yes     6/5/2006 4:00:00 AM
> 3     5       No      6/5/2006 5:00:00 AM
> 3     6       Yes     6/5/2006 6:00:00 AM
> 4     7       No      6/5/2006 7:00:00 AM
> 4     8       No      6/5/2006 8:00:00 AM
> 
> 
> query --
> 
> SELECT a.id_i, a.ir_id, a.test, max(a.stamp) as
> mstamp  -- PostgreSQL might not require an
> aggregate with the group by.
> 
> FROM test a INNER JOIN 
> (
> SELECT Max(stamp) AS tmax, id_i
> FROM test
> group by id_i
> ) b
> 
>  ON a.stamp = b.tmax
> 
> group by a.id_i, a.test, a.ir_id, a.stamp
> 
> having a.test = false
> 
> ORDER BY a.id_i,a.ir_id, a.test
> 
> ;
> 
> results --
> 
> id_i  ir_id   test    mstamp
> 4     8       No      6/5/2006 8:00:00 AM

Richard, that is the result i would need given that
data set.  i have to digest this version, though.

should this query be more efficient than the subquery
version as the table starts to get large?

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