Thanks! But now i have another problem related with count():
select page_id, word, word_position, count(page_id) from (select * from
search_word('word1', 'table1') union search_word('word2', 'table2')) foo
group by page_id;
and gives me "foo.word must appear in GROUP clause or be used in an
aggregate function"
And i want to group by page_id only, because that is what i need to
count. Tips here?
Thanks again man.
Gerardo
am Wed, dem 28.03.2007, um 11:04:29 -0300 mailte Gerardo Herzig folgendes:
Hi dudes, i have the following question
i have 2 tables with the same format, and i want to know if is there a
possibility of using some sort of count(*) for achieving this result:
select a from table1 where (condition) union select a from table2 where
(condition), count(a) group by a
The idea is having how many times (condition) is true for both tables.
Im not shure im explaining myself clearly, my english is not the best
(as you can see ;)
You can use a subselect, a simple example:
test=# select *, count(1) from (select 1 union select 2 union select 3) foo
group by 1;
?column? | count
----------+-------
1 | 1
2 | 1
3 | 1
(3 rows)
Andreas
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