Try this: Select * from view v1 where duration = (select max(duration) from view v2 where v2.phone_number = v1.phone_number)
You could get more than one call listed for the same number if many calls match max(duration) for that number. -----Mensaje original----- De: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] En nombre de Mike Diehl Enviado el: Miércoles, 15 de Agosto de 2007 17:28 Para: SQL Postgresql List Asunto: [SQL] Problem with phone list. Hi all. I've qot a problem I need to solve. I'm sure it's pretty simple; I just can't seem to get it, so here goes... I've got a table, actually a view that joins 3 tables, that contains a phone number, a unique id, and a call duration. The phone number has duplicates in it but the unique id is unique. I need to get a list of distinct phone numbers and the coorisponding largest call duration. I've got the idea that this should be a self-join on phone number where a.id<>b.id, but I just can't seem to get the max duration. Any hints would be much appreciated. Mike. ---------------------------(end of broadcast)--------------------------- TIP 4: Have you searched our list archives? http://archives.postgresql.org ---------------------------(end of broadcast)--------------------------- TIP 5: don't forget to increase your free space map settings
