On Sun, May 11, 2008 at 11:07 PM, Mag Gam <[EMAIL PROTECTED]> wrote: > Hi All, > > I have a view that generates output similar to this. > > select * from foo.view; > > ts | size > -------------------+----- > 2002-03-16 | 11 > 2002-03-17 | 16 > > 2002-03-18 | 18 > 2002-03-19 | 12 > > I am trying to find the difference between the size column. So the desired > output would be > > ts | size| Diff > -------------------+-----+------ > 2002-03-16 | 11 | 0 > > 2002-03-17 | 15 | 4 > 2002-03-18 | 18 | 3 > 2002-03-19 | 12 | -6 > > > I need the first column to be 0, since it will be 11-11. The second colum > is 15-11. The third column is 18-15. The fourth column is 12-18. > > Any thoughts about this?
Try this: select ts, size, t1.size - (select t2.size from foo.view as t2 where t2.ts < t1.ts order by ts desc limit 1) as diff from foo.view as t1 order by ts asc; HTH, -- [EMAIL PROTECTED] [EMAIL PROTECTED] gmail | hotmail | indiatimes | yahoo }.com EnterpriseDB http://www.enterprisedb.com Mail sent from my BlackLaptop device