maria s escreveu:
I tried the query and it is returning result as ,
for a single entry in sample info in separate rows
The result of the query as
1, prop1,value1
1,prop2,value2
2,prop1,value1
2 prop2,value2
2 prop3,value3
but i want the output as single row per sample id like
1,value1,value2
2 value1,value2,value3
Is this possible? or functions will help to get the result?
Try tablefunc/crosstab:
http://www.postgresql.org/docs/current/interactive/tablefunc.html
please help.
Thanks,
-maria
On Tue, Jun 10, 2008 at 11:03 AM, Pavel Stehule <[EMAIL PROTECTED]
<mailto:[EMAIL PROTECTED]>> wrote:
Hello
SELECT i.name <http://i.name>, p.property_name, p.property_value
FROM sample_info i
JOIN
sample_properties p
ON i.id <http://i.id> = p.id <http://p.id>
maybe
Pavel
2008/6/10 maria s <[EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]>>:
> Hello friends,
> I need help in write a query.
>
> I have 2 tables, one is sample_info and sample_properties,
>
> sample_info (id integer, string name)
> ------------------
> 1, c_01
> 2, c_02
> ...
>
> sample_properties(sample_id integer(ref. sample_info),
property_name string
> ,property_value string )
> -------------------------
> 1, prop1, value1
> 1, prop2, value2
> 2, prop1, value1
> 2, prop2, value 2
> 2, prop3, value3
>
>
> I would like to get the result by joining 2 tables, for sample
id 1 from
> sample_info, the result should be
>
> 1,c_01,value1,value2
>
> for sample 2
>
> 2, c_02,value1,value2,value3
>
> with property_value column header as property_name
>
> Can anyone help me to write a query /function/view to get the
above output?
>
Osvaldo
--
Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org)
To make changes to your subscription:
http://www.postgresql.org/mailpref/pgsql-sql
