Hello It cannot work, you mix the sql with plpgsql language
2010/8/17 Imre Horvath <blemi...@gmail.com>: > Hi! > > My question is, how can I get the out parameter from a function with > SELECT INTO by name? > I mean: > > create function testfunc1(OUT _status integer) returns integer as > $BODY$ > _status := 0; > $BODY$ > language plpgsql; > > create function testfunc2() as > declare > status integer; > $BODY$ > select into status * from testfunc1(); > $BODY$ > language plpgsql; > > create function testfunc3() as > declare > status integer; > $BODY$ > select into status _status from testfunc1(); > $BODY$ > language plpgsql; > > testfunc2 works, testfunc3 not. > > Thanks in advance: > Imre Horvath > > create or replace function test1(out _status integer) returns integer as $$ begin _status := 10; end; $$ language plpgsql; create or replace function test3() returns void as $$ declare status integer; begin select into status _status from test1(); raise notice '%', status; end; $$ language plpgsql; this working for me. postgres=# select test3(); NOTICE: 10 test3 ─────── (1 row) Regards Pavel Stehule > -- > Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) > To make changes to your subscription: > http://www.postgresql.org/mailpref/pgsql-sql > -- Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org) To make changes to your subscription: http://www.postgresql.org/mailpref/pgsql-sql
