Suppose I run the following query:

    WITH "exp" AS (
        DELETE FROM "item" i
        USING "item_expired" e
        WHERE   e.oref      = i.ref
            AND i.basket    = $1
        RETURNING i.basket, e.oref, e.nref, i.count, e.msg
    ),
    "subst" AS (
        INSERT INTO "item" ("basket", "ref", "count")
        SELECT e.basket, e.nref, e.count
        FROM "exp" e
        WHERE e.nref IS NOT NULL
    )
    SELECT DISTINCT e.msg
    FROM "exp" e

This is a very convenient and somewhat more flexible alternative to
INSERT... DELETE RETURNING (which doesn't work). However, the "item"
table has a unique constraint on (basket, ref), so sometimes I need to
update instead of insert; to handle this I have a VOLATILE function,
add_item. Unfortunately, if I call it the obvious way

    WITH "exp" AS ( -- as before
    ),
    "subst" AS (
        SELECT add_item(e.basket, e.nref, e.count)
        FROM "exp" e
        WHERE e.nref IS NOT NULL
    )
    SELECT DISTINCT e.msg
    FROM "exp" e

then the planner sees that the results of "subst" are not used, and
doesn't include it in the query plan at all.

Is there any way I can tell WITH that add_item is actually a data-
modifying statement? Adding FOR UPDATE doesn't seem to help (I didn't
really expect it would.)

Alternatively, are either of these safe (that is, are they guaranteed to
call the function once for every row returned by "exp", even if the
DISTINCT ends up eliminating some of those rows)?

    WITH "exp" AS ( -- as before
    ), "subst" AS ( -- SELECT add_item(...) as before
    )
    SELECT DISTINCT e.msg
    FROM "exp" e
        LEFT JOIN "subst" s ON FALSE

    WITH "exp" AS ( -- as before
    )
    SELECT DISTINCT s.msg
    FROM (
        SELECT e.msg, CASE
            WHEN e.nref IS NULL THEN NULL
            ELSE add_item(e.basket, e.nref, e.count)
        END "subst"
    ) s

I don't like the second alternative much, but I could live with it if I
had to.

Ben



-- 
Sent via pgsql-sql mailing list (pgsql-sql@postgresql.org)
To make changes to your subscription:
http://www.postgresql.org/mailpref/pgsql-sql

Reply via email to