On 11/07/2010 08:06 PM, Guillermo Polito wrote:
#anySatisfy: does not iterate over the entire collection either. So if you only want to know if there is one that satisfies the condition... this is the message you're looking for.Cheers! Guille
And finally, a generic "trick" for breaking out of loops (not just iterations over collections):
Factor out the loop in a single method, then call it. When you want to break out, just do a normal return!
regards, Göran
