Henrik Sperre Johansen wrote:
>
>
>
> Den 16.12.2010 14:48, skrev flebber:
>> HI
>>
>> doing the pharo tutorial and I wanted to know how pharo viewed the
>> dynamic
>> array at index 3(seems smalltalk starts at 1 not 0)
>>
>> >From the xample simple enough
>> { (2+3) . (6*6) . 'hello', ' Stef'} size. 3
>>
>> from the strings example we found index by
>>
>> 'ProfStef' at: 1. $P
>>
>> so I thought { (2+3) . (6*6) . 'hello', ' Stef'} at 3. would let me know
>> what the array was evaluated to after execution but it doesn't. Is it
>> confused because it doesn't know whether I want the third array element
>> or
>> the third character?
>>
>> Led me to wonder the correct way if doing this, so that I could evaluate
>> array 1 * 2.
>>
>> { (2+3) . (6*6) . 'hello', ' Stef'} at 1 * at 2. 180
>>
>>
>> Cheers
>
> What do you mean?
> The dynamic array is created with three elements,
> 5 (2+3) at index 1,
> 36 (6*6) at index 2, and
> 'hello Stef' ('hello', ' Stef') at index 3.
>
> at: 3 thus returns the string.
> at 3 is invalid, as it is basically 2 method calls, array does not
> understand a message called #at, and #3 is an invalid selector anyways.
>
> For your second expression, writing
> ({ (2+3) . (6*6) . 'hello', ' Stef'} at: 1) * (at: 2) would not work,
> as you're missing the receiver for the second at: call.
> you'd need to do something like:
> array := { (2+3) . (6*6) . 'hello', ' Stef'}.
> (array at: 1) * (array at: 2). 180
>
> Cheers,
> Henry
>
>
>
>
>
Yes so simply if at 1 returns the first element of a string, what returns
the third element of dynamic array, do you have to assign a varaible for the
array to be able to retrieve elements?
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