ID: 15866 Updated by: [EMAIL PROTECTED] Reported By: [EMAIL PROTECTED] Status: Bogus Bug Type: Scripting Engine problem Operating System: Linux PHP Version: 4.0.6 New Comment:
The something else is bogus too. From the manual: echo() is not actually a function (it is a language construct) ... and print() is not actually a function (it is a language construct) .... So the phrase "is a language construct" alone doesn't weight much. There *is* a difference, but it's not the 'being a language construct'. Previous Comments: ------------------------------------------------------------------------ [2002-03-05 01:29:16] [EMAIL PROTECTED] echo is a language construct and not a function. It's different this way from print which is a function (a built-in one). Not a bug -> Bogus Derick ------------------------------------------------------------------------ [2002-03-05 00:22:42] [EMAIL PROTECTED] The last sentence if wrong. print actually returns a value (as stated in the manual), maybe that's the difference. ------------------------------------------------------------------------ [2002-03-05 00:19:03] [EMAIL PROTECTED] I've found such differences some time ago (but didn't care about it yet). E.g. <? $a = (echo "test\n"); var_dump($a); ?> <-- parser error <? $a = (print "test\n"); var_dump($a); ?> <-- outputs 1 'print' always evals to int(1) ------------------------------------------------------------------------ [2002-03-04 23:31:57] [EMAIL PROTECTED] Using Echo in expression 3 of a for loop creates a parse error. For instance: $blah = (0,1,2,3,4,5,6,7,8,9); for ($i = 0; $i < 10; echo $blah[$i++]); results in this error: Parse error: parse error, expecting `')'' in /home/chunky/public_html/test.php on line XX (line of for loop) However, this will parse properly: $blah = (0,1,2,3,4,5,6,7,8,9); for ($i = 0; $i < 10; print $blah[$i++]); ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=15866&edit=1
