ID: 16298
Updated by: [EMAIL PROTECTED]
Reported By: [EMAIL PROTECTED]
-Status: Open
+Status: Bogus
Bug Type: Unknown/Other Function
Operating System: WinXP
PHP Version: 4.1.2
New Comment:
This is just not possible, and I don't see any need for it. Just use
function foo($bar) {}.
Previous Comments:
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[2002-03-26 21:10:01] [EMAIL PROTECTED]
When making a simple function...
<?php
function include_page ($script_prefs[templated_file]) {
$script_prefs["templated_file_extension"] = substr
($script_prefs["templated_file"], strrpos
($script_prefs["templated_file"], ".") +1);
if (($script_prefs["templated_file_extension"] != "php") || (eregi
("^[_a-z0-9-]+$", $script_prefs["templated_file"])) || (file_exists
("C:\\Apache\\htdocs\\templates\\" . $script_prefs["templated_file"])))
{
include_once ("C:\\Apache\\htdocs\\templates\\" .
$script_prefs["templated_file"]);
} else {
include_once ("C:\\Apache\\htdocs\\templates\\error.php");
}
return;
}
?>
(Small scale beta templating system)
When you call the function include_page function with a normal
variable...
i.e. "function include_page($variable)" the function works find...
...but...
If you use it with a variable...
i.e. "function include_page($script_pref["variable"])" the webpage
produces the following...
Parse error: parse error, expecting `')'' in c:\apache\htdocs\index.php
on line 2
I have rewritten the function name sveral times, and in diffrent
forms.. with 's and without.. but no change.. only when you use a
variable inside a array...
My PHP.ini has full error reporting, a debugging mode switched on
(startup errors etc on)
------------------------------------------------------------------------
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Edit this bug report at http://bugs.php.net/?id=16298&edit=1
