ID: 16857
Updated by: [EMAIL PROTECTED]
Reported By: [EMAIL PROTECTED]
-Status: Feedback
+Status: Closed
Bug Type: Feature/Change Request
Operating System: Any
PHP Version: 4.2.0
New Comment:
I backtraced my sources and I seem to have combined the fact that
arithmetic expressions can't be used on static vars, with the short
if-statement.
Besides the code I submited, I also used:
<?php
function testint($row=-1)
{
static $currentrow=-1;
$currentrow=($row == -1) ? $currentrow++ : $row;
echo "$currentrow\n";
}
?>
which didn't increment $currentrow, nor did it issue any warning.
When looking for info, I found the user-contributed message:
http://www.php.net/manual/en/language.variables.scope.php
By [EMAIL PROTECTED], at 10-Dec-2001:
static $var = 2+3; //any expression
which lead me to believe that also () ? : expressions wouldn' t work,
but it's the actual assignment that is ignored.
Previous Comments:
------------------------------------------------------------------------
[2002-04-28 20:03:21] [EMAIL PROTECTED]
Works fine for me. Can you please add a short and complete
example which shows clearly what you're exactly asking for?
--Jani
------------------------------------------------------------------------
[2002-04-26 12:09:37] [EMAIL PROTECTED]
Would be nice if this worked. But the short syntax isn't accepted for a
static var, even it's not in the initial declaration.
<?php
function sql_num_rows($result)
{
static $cmd='undefined';
if($cmd == 'undefined')
{
$cmd=($this->pg_new_api) ? 'pg_num_rows' : 'pg_numrows';
}
return @$cmd($result);
}
?>
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=16857&edit=1
