ID: 17282
Updated by: [EMAIL PROTECTED]
Reported By: [EMAIL PROTECTED]
-Status: Open
+Status: Bogus
Bug Type: Scripting Engine problem
Operating System: FreeBSD 4.4-STABLE
PHP Version: 4.2.1
New Comment:
You can't compare floats like this, a float is an approximation of the
number, but never exact the number.
This is not a bug, this wouldn't work in most languages, including C ->
Bogus
Previous Comments:
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[2002-05-16 22:23:02] [EMAIL PROTECTED]
This problem also occurs on PHP 4.1.2.
The following code fragment produces very odd results:
<?
$a = array(41.96, 20.97, 20.99);
$t = 0;
for($i = 1; $i < count($a); $i++)
$t += abs($a[$i]);
echo "$t != $a[0]\n";
var_dump($t != $a[0]);
echo "t = ";
var_dump($t);
echo "a[0] = ";
var_dump($a[0]);
?>
The results are shown below:
41.96 != 41.96
bool(true)
t = float(41.96)
a[0] = float(41.96)
Both variables appear to be the same type, and look the same, yet
compare incorrectly with both typed and untyped comparisons.
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Edit this bug report at http://bugs.php.net/?id=17282&edit=1
