ID: 42961
Updated by: [EMAIL PROTECTED]
Reported By: wilsonwg at gmail dot com
-Status: Open
+Status: Feedback
Bug Type: MySQLi related
Operating System: Windows XP SP2
PHP Version: 5.2.4
New Comment:
Try turning on error_reporting = E_ALL and/or add some checks in your
code for errors. Similar stuff works just fine for me so I think you
just have some problem with your query.
Previous Comments:
------------------------------------------------------------------------
[2007-10-14 11:26:29] wilsonwg at gmail dot com
Oops, and the second last line in my code should be:
$id = $result['id'];
------------------------------------------------------------------------
[2007-10-14 11:24:35] wilsonwg at gmail dot com
I forgot to add under score in my result sections.
SELECT * FROM compounds where compound_name = 'item 1'
Should be:
SELECT * FROM compounds where compound_name = 'item_1'
------------------------------------------------------------------------
[2007-10-14 11:20:13] wilsonwg at gmail dot com
Description:
------------
I set up an array in the code and then use the for loop to query my
database. However, the mysqli functions would not return the result
values.
This is the table used for the query(columns separated a comma):
-------------
id, item_name
-------------
1, item_1
2, item_2
3, item_3
4, item_4
-------------
Reproduce code:
---------------
$mysqli_connect =mysqli_connect("localhost", "root", "password",
"myDB");
$array_items = "item_1,item_2,item_3,item_4";
$array_list = explode (",", $array_items);
for ($i=0; $i<count($array_list); $i++){
$select_item = "SELECT * FROM compounds where item_name =
'".$array_list[$i]."'";
echo "$select_item <p>";
$search_item_query = mysqli_query($mysqli_connect, $select_item);
$result = mysqli_fetch_array($search_item_query);
$id = $result['item_id'];
echo "$id <p>";
}
Expected result:
----------------
SELECT * FROM compounds where compound_name = 'item 1'
1
SELECT * FROM compounds where compound_name = 'item 2'
2
SELECT * FROM compounds where compound_name = 'item 3'
3
SELECT * FROM compounds where compound_name = 'item 4'
4
Actual result:
--------------
SELECT * FROM compounds where compound_name = 'item 1'
SELECT * FROM compounds where compound_name = 'item 2'
SELECT * FROM compounds where compound_name = 'item 3'
SELECT * FROM compounds where compound_name = 'item 4'
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=42961&edit=1
