ID: 42409
Comment by: ayvah at nessness dot org
Reported By: luke dot mcildoon at niche dot com dot au
Status: No Feedback
Bug Type: Scripting Engine problem
Operating System: Windows Vista 32-bit
PHP Version: 5.2.3
New Comment:
I don't know if this bug has been fixed by this point, but I would like
to confirm it in PHP version 5.2.4, in Ubuntu 8.04.
It's fairly simple to invoke the bug. Essentially, when you access a
value in an ArrayObject that doesn't exist, you seem to get NULL and
you're able to treat the empty "NULL" value returned by an array as if
it were an array.
I've had a look around, and I can't find any other mention of the bug,
so I'm kind of assuming it's still present.
$array = new ArrayObject();
$array['notinarray'][] = "value";
var_dump($var['something']);
var_dump($var2['somethingelse']);
var_dump($var3[0]);
Output:
array(1) { [0]=> string(5) "value" }
array(1) { [0]=> string(5) "value" }
string(5) "value"
Previous Comments:
------------------------------------------------------------------------
[2007-09-01 01:00:01] php-bugs at lists dot php dot net
No feedback was provided for this bug for over a week, so it is
being suspended automatically. If you are able to provide the
information that was originally requested, please do so and change
the status of the bug back to "Open".
------------------------------------------------------------------------
[2007-08-24 09:59:50] [EMAIL PROTECTED]
How about you first provided an example script that has some way of
working even the wrong way? The one here just says "Fatal error: Call to
undefined function session()"
------------------------------------------------------------------------
[2007-08-24 06:55:54] luke dot mcildoon at niche dot com dot au
Description:
------------
I have a class that returns an array by reference using __get(). As
soon as you try to set a 2+ dimension on the array, the -> operator
returns whatever you tried to assign to the referenced array.
ie.
session()->session['foo'][] = 'test';
print_r($this->var); #[0] => 'test'
print_r($asdf->ghjk); #[0] => 'test'
Basically, from any point after the first example line is used, any use
of the -> operator, regardless of the object being referenced, will
return whatever you tried to assign to the referenced array.
Reproduce code:
---------------
class session extends ArrayObject
{
public $data = array();
public function &__get($var)
{
if($var == 'session')
{
return $this;
}
}
}
session()->session[][] = 'test';
print_r($this->var);
print_r($anything->var);
print_r($this->foobar);
Expected result:
----------------
The actual value of $this->var, then undefined property warnings.
Actual result:
--------------
[0] => 'test'
[0] => 'test'
[0] => 'test'
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=42409&edit=1
