ID:          43983
 Updated by:  [EMAIL PROTECTED]
 Reported By: rubens21 at gmail dot com
-Status:      Open
+Status:      Bogus
 Bug Type:    Scripting Engine problem
 PHP Version: 5.2.5
 New Comment:

Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php




Previous Comments:
------------------------------------------------------------------------

[2008-04-07 19:02:45] ben at mailinator dot com

How is this weird?  $test is an object.  You store a reference to
$test, 
and then you modify $test.  Since you only stored a reference to the 
original object, of course you will see the new value when you print
out 
the reference.

This changed between PHP4 and PHP5.  PHP4 stores a copy rather than a 
reference.  If you are looking for the PHP4 behavior, you can use the 
"clone" keyword.  e.g. $Objeto->valorDeTeste[] = clone $test;

------------------------------------------------------------------------

[2008-02-24 20:17:54] rubens21 at gmail dot com

I'm sorry, 'The same' = 'The same problem'

CODE:
$test = new stdClass();
$Objeto = new stdClass();

$test->valor = "The first value";
$Objeto->valorDeTeste[] = $test;

$test->valor = "The second value";

echo "<pre>";
print_r($Objeto->valorDeTeste);
echo "<br />";
var_dump($Objeto->valorDeTeste);
echo "</pre>";








Array
(
    [0] => stdClass Object
        (
            [valor] => The second value
        )

)

array(1) {
  [0]=>
  object(stdClass)#1 (1) {
    ["valor"]=>
    string(16) "The second value"
  }
}

------------------------------------------------------------------------

[2008-02-24 19:44:21] [EMAIL PROTECTED]

That's impossible, the output of var_dump() differs a LOT from
print_r(). So can you please really test it?

------------------------------------------------------------------------

[2008-02-23 17:04:12] rubens21 at gmail dot com

"What does it output when you replace print_r() with var_dump() ?"

R: The same

------------------------------------------------------------------------

[2008-02-01 22:28:15] [EMAIL PROTECTED]

What does it output when you replace print_r() with var_dump() ?

------------------------------------------------------------------------

The remainder of the comments for this report are too long. To view
the rest of the comments, please view the bug report online at
    http://bugs.php.net/43983

-- 
Edit this bug report at http://bugs.php.net/?id=43983&edit=1

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