ID:               45840
 User updated by:  trendboy at gmail dot com
 Reported By:      trendboy at gmail dot com
-Status:           Open
+Status:           Closed
 Bug Type:         MySQL related
 Operating System: Linux and Windows
 PHP Version:      5.2.6
 New Comment:

I think I may have fixed it, it seems to be the upload I had was the
problem.


Previous Comments:
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[2008-08-17 12:31:41] trendboy at gmail dot com

Description:
------------
Steps to reproduce:

1) Create a page to read in a JPEG image from a URL location and
inserts into the database to a BLOB.
2) On another page select * from your blob
3) Using any method, myself_fetch_array or assoc get the contents
4) Print or echo it out

You get Resource ID #5

Dump the vars from the result record set and you get
resource 3 type(mysql result)

It's very strange! It should be displaying the content of the blob to
the screen and with the correct mime header set to jpeg it should show
you the image.

I thought maybe it was a bug on the LINUX version so I installed the
windows version and same issue.

Linux version:
/usr/local/php/bin/php --version
PHP 5.2.4 (cli) (built: Sep 17 2007 22:46:56)
Copyright (c) 1997-2007 The PHP Group
Zend Engine v2.2.0, Copyright (c) 1998-2007 Zend Technologies

mysql --version
mysql  Ver 14.12 Distrib 5.0.27, for pc-linux-gnu (i686) using readline
5.0

I tried 5.2.6 on windows.

It's a right head-wrecker :) Is it a bug?

Reproduce code:
---------------
The code (shortened of course)

my insert is (after I get it from a URL etc): 
mysql_query("insert into thumbnail (image) values ('" .
addslashes($img) . "')");

then to read it:

$sql = "select * from thumbnail where id = 1";
$result = mysql_query($sql);
 var_dump($result);
while ($row = mysql_fetch_assoc($result)){

echo $row[image];
}


Expected result:
----------------
You should see your image



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