ID: 19943
Comment by: [EMAIL PROTECTED]
Reported By: [EMAIL PROTECTED]
Status: Open
Bug Type: Arrays related
Operating System: Win2K
PHP Version: 4.2.1
New Comment:
However, the following codes does work, even though the array is still
ragged:
<?
$ragged = array();
for ( $count = 0; $count < 10; $count++ )
{
$ragged['idx'][$count] = 'ragged '.$count;
$ragged[$count] = 'single '.$count;
}
?>
<html><head></head><body>
<table border="1">
<tr>
<td>Expected</td><td>Actual</td>
<td>Expected IDX</td><td>Actual IDX</td>
</tr>
<?
for ( $count = 0; $count < 10; $count++ )
{
?>
<tr>
<td> <?= 'single '.$count ?> </td><td> <?= $ragged[$count] ?> </td>
<td> <?= 'ragged '.$count ?> </td><td> <?= $ragged['idx'][$count] ?>
</td>
</tr>
<? } ?>
</table></body></html>
Previous Comments:
------------------------------------------------------------------------
[2002-10-16 19:50:57] [EMAIL PROTECTED]
When using an array that has ragged indices, the value in the array is
undefined. Well, actually it can be defined, but it is unexpected. No
errors or warnings are reported. Sample Code:
<?
$ragged = array();
for ( $count = 0; $count < 10; $count++ )
{
$ragged[$count] = 'single '.$count;
$ragged[$count]['idx'] = 'ragged '.$count;
}
?>
<html><head></head><body>
<table border="1">
<tr>
<td>Expected</td><td>Actual</td>
<td>Expected IDX</td><td>Actual IDX</td>
</tr>
<?
for ( $count = 0; $count < 10; $count++ )
{
?>
<tr>
<td> <?= 'single '.$count ?> </td><td> <?= $ragged[$count] ?> </td>
<td> <?= 'ragged '.$count ?> </td><td> <?= $ragged[$count]['idx'] ?>
</td>
</tr>
<? } ?>
</table></body></html>
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=19943&edit=1
