ID: 47459
User updated by: ben dot keen at gmail dot com
Reported By: ben dot keen at gmail dot com
-Status: Feedback
+Status: Closed
Bug Type: Reproducible crash
Operating System: Linux
PHP Version: 5.2.8
New Comment:
Closed.
Previous Comments:
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[2009-02-20 21:21:11] ben dot keen at gmail dot com
Apologies, I don't think that is a bug. There's something wonky going
on on the server. Now even this isn't working:
<?php
echo "hello.";
exit;
?>
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[2009-02-20 13:16:59] j...@php.net
Thank you for this bug report. To properly diagnose the problem, we
need a short but complete example script to be able to reproduce
this bug ourselves.
A proper reproducing script starts with <?php and ends with ?>,
is max. 10-20 lines long and does not require any external
resources such as databases, etc. If the script requires a
database to demonstrate the issue, please make sure it creates
all necessary tables, stored procedures etc.
Please avoid embedding huge scripts into the report.
------------------------------------------------------------------------
[2009-02-20 07:11:28] ben dot keen at gmail dot com
Description:
------------
This was actually found on 5.2.8, the current main PHP release (not
sure why it's not listed in the PHP version dropdown on the bug report
page... ??)
The problem is this: I'm importing a number of PHP files with
require_once() into a main page but I get a blank page. I debugged it
down to two lines of code in one of the files file that is being
included. These two lines are inside a function that is NOT called,
however.
if (!$something)
ft_handle_error("one" . "two" . "three", mysql_error());
When I comment these two lines out, the page loads fine. No errors,
notifications or warnings are displayed. When I remove one (any) of the
strings being concatenated in the first function parameter, the page
loads fine. In other words, when I change the lines to any of these, the
page loads fine:
if (!$something)
ft_handle_error("two" . "three", mysql_error());
As does:
if (!$something)
ft_handle_error("one" . "three", mysql_error());
As does:
if (!$something)
ft_handle_error("one" . "two", mysql_error());
Two final things to mention: when I remove the second mysql_error()
parameter but keep all three strings being concatenated in the first
parameter, the page loads. Also, when I remove the if (!$something)
condition and keep all three strings being concatenated again, it also
works fine. The actual strings being concatenated don't seem to make any
difference.
I'm well beyond confused. Debugging tips?
Reproduce code:
---------------
if (!$something)
ft_handle_error("one" . "two" . "three", mysql_error());
Expected result:
----------------
The page should load for ANY of the lines of PHP code mentioned.
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Edit this bug report at http://bugs.php.net/?id=47459&edit=1
