Edit report at http://bugs.php.net/bug.php?id=52321&edit=1
ID: 52321
Updated by: ras...@php.net
Reported by: saltybaldyev at gmx dot com
Summary: list() fails under a mere condition
-Status: Open
+Status: Bogus
Type: Bug
Package: Variables related
Operating System: linux,windows
PHP Version: 5.3.2
New Comment:
You are overwriting the variable you are iterating over. Just like with
a foreach
loop, there is no defined behaviour for that. In this case it is
assigned things
right to left so $b gets set to "yeah" first and then $a gets set to the
first
array element of "yeah" which, since it is a string, is 'y'.
Previous Comments:
------------------------------------------------------------------------
[2010-07-12 20:58:28] saltybaldyev at gmx dot com
the same if we do list($a,$b,$c)=$c, list($a,$c,$b)=$c and so on.
i guess such assignments only work properly in case its right part goes
to list() first: list(--> $c <--,$a1,$a2,$a3,...)=$c
------------------------------------------------------------------------
[2010-07-12 20:52:11] saltybaldyev at gmx dot com
Description:
------------
let $b=array(# , #).
then
list($a,$b) = $b
fails.
moar precise: after the assigment we'd get
$b = $b[1],
$a = {
$b[1][0], if $b[1] is a string/array
NULL, if $b[1] is a number
}
if $b[1] is an object we'd get a fatal error 'cant convert
object->array'.
//////////////////
it works correctly if we try list($b,$a)=$b. so an easy fix could be
forged in just 2 additional steps: swap arguments * do the usual work *
swap results
Test script:
---------------
$a = 1;
$b = array('ohno','yeah');
list($a,$b) = $b;
print_r(array('a'=>$a,'b'=>$b));
Expected result:
----------------
Array
(
[a] => ohno
[b] => yeah
)
Actual result:
--------------
Array
(
[a] => y
[b] => yeah
)
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/bug.php?id=52321&edit=1
