Edit report at http://bugs.php.net/bug.php?id=48984&edit=1
ID: 48984
Comment by: giorgio dot liscio at email dot it
Reported by: themastersleader at hotmail dot com
Summary: Strict errors when implementing an interface (with
private methods)
Status: Bogus
Type: Bug
Package: Class/Object related
Operating System: Win XP
PHP Version: 5.3.0
New Comment:
ok i got it
i'm sorry... a private method cannot obviously public in subclasses
-__-
so you are saying that any class can have ---their own method with same
name with totally different signature---...
because private methods does not depends by parent ones
ok now i think that you are right
fields works right... here is the proof:
class A
{
private $test;
public function __construct(){$this->test = "THIS IS A";}
}
class B extends A
{
private $test;
public function printit(){echo isset($this->test) ?: '$this->test is
not set';}
}
$b = new B();
$b->printit();
as you can see every class has its own field with the same name
subclass-field does not inherits parent class's field
Previous Comments:
------------------------------------------------------------------------
[2010-07-15 20:09:47] itay dot malimovka at gmail dot com
"a private method is exactly like the others... explained by the fact
that a private method can be public in a subclass"
Nooooo
Here, try this:
class A{private function x(){}}
class B extends A{public function b(){x()}}
as you can see, class b DID NOT inherited function x, it can call it
from the parent class though, which is what you showed.
Any way, see discussion here:
http://stackoverflow.com/questions/3258523/is-this-a-php-bug-subclasses-must-declare-private-methods-with-the-same-signatur
------------------------------------------------------------------------
[2010-07-15 19:15:21] giorgio dot liscio at email dot it
a private method is exactly like the others... explained by the fact
that a private method can be public in a subclass
class A{private function x(){}}
class B extends A{public function x(){parent::x()}}
------------------------------------------------------------------------
[2010-07-15 15:16:40] itay dot malimovka at gmail dot com
@giorgio dot liscio at email dot it
This is **ONLY** true when the method is protected or public.
------------------------------------------------------------------------
[2010-07-15 11:20:50] themastersleader at hotmail dot com
Quote "extending a method means that in the sub-class the overrided
method can be used as can i use it in the parent class"
The problem is that the sub-class isn't extending the method this
because the method is defined as private.
------------------------------------------------------------------------
[2010-07-15 09:25:23] giorgio dot liscio at email dot it
this is not a bug
extending a method means that in the sub-class the overrided method can
be used as can i use it in the parent class
so
if i have
function test($a, $b, $c){}
in the subclasses every additional parameter must be "not required" to
make the method working
function test($a, $b, $c, $d=NULL, $e=NULL, $f=NULL)
=NULL means that are not required
so in your code
class ChildClass extends ParentClass
{
public function foo(array $content=NULL) { }
}
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