Edit report at http://bugs.php.net/bug.php?id=52794&edit=1
ID: 52794
Updated by: cataphr...@php.net
Reported by: seroshkin at gmail dot com
Summary: $a = $b = $c = $d logic with ArrayObject
-Status: Open
+Status: Bogus
Type: Bug
Package: Arrays related
PHP Version: 5.3.3
Block user comment: N
New Comment:
This is not a bug.
You did not override offsetSet. The assignment returns the assigned
value, hence $b will be 'Fail' in the first example.
However, in the second, despite $o[1] = 'Fail';, $o[1] will return 'Ok'
due to your definition of offsetGet and $b will be 'Ok'.
Previous Comments:
------------------------------------------------------------------------
[2010-09-07 16:53:29] seroshkin at gmail dot com
Description:
------------
If i use expression like
$a = $b = $c = $d;
where $b or $c determined as class extends ArrayObject, then
ArrayObject::offsetGet method do not call.
It may be only if above expression interpreted as
$a = $d;
$b = $d;
$c = $d;
Test script:
---------------
class foo extends ArrayObject{
function offsetGet($index){return 'Ok';}
}
$o = new foo();
$a = $o[1];
$b = ($o[1] = 'Fail');
echo $a,$b;
//Output: OkFail
//but if
$o[1] = 'Fail';
$b = $o[1];
echo $a,$b;
//Output: OkOk
------------------------------------------------------------------------
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Edit this bug report at http://bugs.php.net/bug.php?id=52794&edit=1
